$\lg 10^a=a$
$10^{\lg a}=a$
Oppgave 1
-
\begin{align}\lg 10
&= \lg 10^1\\
&=1
\end{align} -
\begin{align}\lg 100 &= \lg 10^2\\
&=2
\end{align} -
\begin{align}
\lg 1000 &=\lg 10^3\\
&=3\lg 10\\&=3
\end{align} -
\begin{align}\lg 1
&= \lg 10^0\\
&=0
\end{align}
Oppgave 2
Bruk definisjonen for å finne verdien til logaritmene.
Det kan være lurt å tenke potenstall…..
-
\begin{align}\lg 0,1
&= \lg 10^{-1}\\
&=-1
\end{align} -
\begin{align}\lg 0,01 &= \lg 10^{-2}\\
&=-2
\end{align} -
\begin{align}\lg 0,001
&= \lg 10^{-3}\\
&=-3
\end{align} -
\begin{align}&\lg 0\\
\text{finnes ikke }
\end{align}
Oppgave 3
Bruk definisjonen for å finne verdien til logaritmene.
-
\begin{align}\lg \sqrt{10}
&= \lg 10^{\frac{1}{2}}\\
&=\frac{1}{2}
\end{align} -
\begin{align}\lg \sqrt{10} = \end{align}
-
\begin{align}\lg 10^{\frac{2}{3}}=\frac{2}{3}\end{align}
Oppgave 4
Bruk definisjonen for å finne verdien til logaritmene.
-
\begin{align}
10^{\lg 10}
&=10
\end{align} -
\begin{align}
10^{\lg 0.5}
&=10^{\lg \frac{1}{2}}\\
&=\frac{1}{2}
\end{align} -
\begin{align}
10^{(\lg 2+\lg 3)}
&=10^{\lg(2\cdot 3)}\\
&=6
\end{align}
Oppgave 5
$\lg(xy)+\lg x=$
$\lg x^2+\lg xy-\lg y=$
Bruk reglen for å forenkle logaritmen.
-
\begin{align}
10^{2\lg 5}
&=10^{\lg 5^2}\\
&=25
\end{align} -
\begin{align}
10^{3\lg 2}
&=10^{\lg 2^3}\\
&=8
\end{align} -
\begin{align}
10^{\frac{\lg 9}{2}}
&=10^{\lg 3}\\
&=3
\end{align}\begin{align}
\frac{\lg 9}{2}
&=\frac{1}{2}\lg 9\\
&=\lg 9^{1}{2}\\
&=\lg \sqrt{9}\\
&=\lg 3
\end{align} -
\begin{align}
10^{\frac{\lg 64}{3}}
&=10^{\lg 4}\\
&=4
\end{align}\begin{align}
\frac{\lg 64}{3}
&=\frac{1}{3}\lg 4^3\\
&=\lg 4^{3\cdot \frac{1}{3}}\\
&=\lg 4
\end{align}
Oppgave 6
-
\begin{align}
\lg \sqrt[3]{x}+\lg \sqrt[3]{x^2}
&=\lg x^{\frac{1}{3}}+\lg x^{\frac{2}{3}}\\
&=\lg (x^{\frac{1}{3}}\cdot x^{\frac{2}{3}})\\
&=\lg (x^{\frac{1}{3}+\frac{2}{3}})\\
&=\lg x
\end{align} -
\begin{align}
\lg x^2y-\lg y
&=2\lg x+\lg y-\lg y\\
&=2\lg x
\end{align} -
\begin{align}\lg \sqrt{x^3}=\end{align}
-
\begin{align}\lg(x^2)^3=\end{align}
-
\begin{align}\lg 2x^3=\end{align}
-
\begin{align}
\lg \frac{x^2}{y^2}+\lg\frac{y}{x}
&=
\end{align}
-
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